Q is the image of point P(1, -2, 3) with respect to the plane `x-y+z=7`. The distance of Q from the origin is.

Let P be the image of the point (3, 1, 7) with respect to the plane x-y+z=3 . Then, the equation of the plane passing through P and containing the straight line (x)/(1)=(y)/(2)=(z)/(1) is

Let P be the image of the point (3, 1, 7) with respect to the plane x-y+z=3 . Then, the equation of the plane passing through P and containing the straight line (x)/(1)=(y)/(2)=(z)/(1) is

Let P be the image of the point (3, 1, 7) with respect to the plane x -y + z = 3 . Then, the equation of the plane passing through P and containing the straight line (x)/(1) = (y)/(2) = (z)/(1) is

Let P be the image of the point (3, 1, 7) with respect to the plane x-y+z=3 . The equation of the plane passing through P and parallel to x-2y+3z=7 is

Let P be the image of the point (3, 1, 7) with respect to the plane x-y+z=3 . The equation of the plane passing through P and parallel to x-2y+3z=7 is

Let P be the image of the point (3,1,7) with respect to the plane x - y + z =3. Then the equation of the plane passing through P and containing the straight line x/1 = y/2 = z/1

Find the image of the point (p, q, r) with respect to the plane 2x+ y + z = 6. Hence find the image of the line (x-1)/2=(y-2)/1=(z-3)/4 with respect to the plane.

Let P be the image of the point (3,1,7) with respect to the plane x-y+z=3. then the equation o the plane passing through P and containing the straight line (x)/(1) =(y)/(2) =(z)/(1)