Find the equation of the plane perpendicular to the line `(x-1)/2=(y-3)/(-1)=(z-4)/2` and passing through the origin.

The cartesian equations of the plane perpendicular to the line (x-1)/(2)=(y-3)/(-1)=(z-4)/(2) and passing through the origin is

The equation of the plane perpendicular to the line (x-1)/1=(y-2)/(-1)=(z+1)/2 and passing through the point (2,3,1), is

The equation of the plane perpendicular to the line (x-1)/(1), (y-2)/(-1), (z+1)/(2) and passing through the point (2, 3, 1) . Is

Prove that the equation of a plane perpendicular to the line x-1=2-y=(z+1)/(2) and passing through (2,3,

Find the equation of the plane passing through the line (x-1)/(5)=(y+2)/(6)=(z-3)/(4) and point (4,3,7)

Find the equation of the line passing through A(0,1,2) and perpendicular to line (x-1)/2=(y+1)/2=(z-1)/3

Find the equation of the plane passing through the straight line (x-1)/(2)=(y+2)/(-3)=(z)/(5) and perpendicular to the plane x-y+z+2=0

Find the equation of the line passing through the point (3,1,2) and perpendicular to the lines (x-1)/1=(y-2)/2=(z-3)/3 and x/(-3)=y/2=z/5