In the figure, `m_(1)=m_(2)=10 kg`. The coefficients of friction between `A, B` and `B`, surface are `0.2`. Find the maximum value of `m_(3)` so that no block slips ( All the pullies are ideal and strings are massless).

In the figure, m _(1) m _(2) =1kg, The co-efficients of friction between A, B and B, surface are 0.2. The maximum value of m, so that no block slips is nx7 the value of n is (All the pullies are ideal and strings are massless).

1 kg and 4 kg blocks lie on a rough horizontal surface. The coefficient of friction between 4 kg blocks and surface is 0.2 while the coefficient of firction between 1 kg blocks and the surface is 0.6 . All the pulley shown in the figure are massless and frictionless and all strings are massless and frictionless and all strings are massless.

In the figure m_(A) = m_(B) = m_(C) = 60 kg . The coefficient of friction between C and ground is 0.5 B and ground is 0.3, A and B is 0.4. C is pulling the string with the maximum possible force without moving. Then the tension in the string connected to A will be

In the figure m_(A) = m_(B) = m_(C) = 60 kg . The coefficient of friction between C and ground is 0.5 B and ground is 0.3, A and B is 0.4. C is pulling the string with the maximum possible force without moving. Then the tension in the string connected to A will be

Two blocks a and B of mass m_(A)=1kg and m_(B)=3kg are kept on the table as shown in figure the coefficient of friction between A and B is 0.2 and between B and the surface of the table is also 0.2 the maximum force F that can be applied on B horizontally, so that the block A does not slide over the block B is [Take g=10m//s^(2) ]

Two blocks A and B of masses m_(A) = 1kg and m_(B) = 3kg are kept on the table as shown in figure. The coefficient of friction between A and B is 0.2 and between B and the surface of the table is also 0.2. The maximum force F that can be applied on B horizontally, so that the block A does not slide over the block B is ________ (in N): [Take g = 10 m//s^(2) ]

Two block tied with a massless string of length 3m are placed on a rotating table as shown. The axis of rotation is 1m from 1kg mass and 2m from 2kg mass. The angular speed omega=4rad//s . Ground below 2kg block is smooth and below 1kg block is rough. (g=10m//s^(2)) (a) Find tension in the string, force of friction on 1kg block and its direction. (b) If coefficient of friction between 1kg block and groung is mu=0.8 . Find maximum angular speed so that neither of the blocksd slips. (c) If maximum tension in the string can be 100N , then maximum angular speed so that neither of the blocks slips.

The coefficient of static friction, mu_(s) between block A mass 2kg and the table as shown in the figure, is 0.2. What would be the maximum mass value of block B, so that the two blocks do not move ? The string and the pulley are asseumed to be smooth and massless ( g=10m//s^(2) )

The coefficient of static friction, mu_(s) between block A of mass 2 kg and the table as shown in the figure is 0.2. What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless. (g=10m//s^(2))

The coefficient of static friction, mu_(s) between block A of mass 2 kg and the table as shown in the figure is 0.2. What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless. (g=10m//s^(2))