`1.245g` of `CuSO_(4).xH_(2)O` was dissolved in water and `H_(2)S` was passed until CuS was completely precipitated. The `H_(2)SO_(4)` Produced in the filtrated required 10 ml of 1N NaOH solution . X cannot be

1.245g of CuSO_(4).xH_(2)O was dissolved in water and H_(2)S was passed until CuS was completely precipitated. The H_(2)SO_(4) Produced in the filtrated required 10 ml of 1M NaOH solution . Calculate X

1.245 g of CuSO_(4). xH_(2)O was dissolved in water and H_(2)S gas was passed through it will till CuS was completely precipitated . The H_(2)SO_(4) produced in the filtrate required 100 ml of 0.1 M NaOH solution . Calculate x (approximately)

1.245 g of a sample of CuSO_4.xH_2O was dissolved in water and H_2S passed till CuS was complete precipitated. The filtrate contained liberated H_2SO_4 , which required 20 " mL of " (N)/(2) NaOH for complete neutralisation. Calculate x, the number of molecules of water associated with CuSO_4(Cu=63.6)

1.245 g of a sample of CuSO_4.xH_2O was dissolved in water and H_2S passed till CuS was complete precipitated. The filtrate contained liberated H_2SO_4 , which required 20 " mL of " (N)/(2) NaOH for complete neutralisation. Calculate x, the number of molecules of water associated with CuSO_4(Cu=63.6)

How many ml of 1 (M) H_(2)SO_(4) is required neutralise 10 ml of 1 (M) NaOH solution?

The volume of 0.1M H_(2)SO_(4) required to neutralise completely 40mL of 0.2M NaOH solution is