Find the equation of line `x+y-z-3=0=2x+3y+z+4` in symmetric form. Find the direction of the line.

Reduce the equation of line x-y+2z=5 adn 3x+y+z=6 in symmetrical form.Or Find the line of intersection of planes x-y+2z=5 and 3x+y+z=6

The equation of straight line 3x+2y-2-4=0;4x+y-2z+3=0 in the symmetrical form is

The equation of the line x+y+z-1=04x+y-2z+2=0 written in the symmetrical form is

The equation of the line x+y+z-1=0 and 4x+y-2z+2=0 written in the symmetrical form is

The symmetric form of the equation of the line x+y-z=1,2x-3y+z=2 is

The equation of line is 2x - 2 = 3y + 1 = 6z - 2 find its direction ratios and also find the vector equation of the line .

The Cartesian equations of a line are (x-3)/(2)=(y+2)/(-5) =(z-6)/(4) Find the vector equations of the line .

The cartesian equation of a line are 6x-2=3y+1=2z-2 . Find its direction ratios and also find the vector of the line.