Find Cartesian and vector equation of the line which passes through the point `(-2,4,-5)` and parallel to the line given by `(x+3)/3=(y-4)/5=(z+8)/6` .

Explanation

To find the Cartesian and vector equations of the line that passes through the point \((-2, 4, -5)\) and is parallel to the line given by \(\frac{x+3}{3} = \frac{y-4}{5} = \frac{z+8}{6}\), we can follow these steps:

### Step 1: Identify the direction ratios of the given line
The given line is represented in symmetric form:
\[ \frac{x+3}{3} = \frac{y-4}{5} = \frac{z+8}{6} \]
From this, we can extract the direction ratios of the line, which are \(3\), \(5\), and \(6\).
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