Find the plane of the intersection of `x^2+y^2+z^2+2x+2y+2=0a n d 4x^2+4y^2+4z^2+4x+4y+4z-1=0.`

(i) Find the equation of the plane passing through the intersection of the planes : 2x - 7y + 4z = 3 and 3x - 5y + 4z + 11 = 0 and the point (-2, 1,3). (ii) Find the equation of plane through the intersection of planes : 3x - y + 2z - 4 = 0 and x + y + z - 2 = 0 and the point (2,2,1) .

The equation of the plane passing through the intersection of the planes x+2y+3z+4=0a dn 4x+3y+2z+1=0 and the origin ils (A) 3x+2y+z+1=0 (B) 3x+2y+z=0 (C) 2x+3y+z=0 (D) x+y+z=0

Find the equation of the plane through the intersection of the planes 3x-4y+5z=10 and 2x+2y-3z=4 and parallel to the line x=2y=3z

Let the equation of the plane containing line x-y-z-4=0=x+y+2z-4 and parallel to the line of intersection of the planes 2x+3y+z=1 and x+3y+2z=2 be x+Ay+Bz+C=0 . Then the values of |A+B+C-4| is …..

The equation of the plane passing through the line of intersection of the planes x+y+z=6 and 2x+3y+4z+5=0 and perpendicular to the plane 4x+5y-3z=8 is

The plane x + 3y + 13 = 0 passes through the line of intersection of the planes 2x - 8y + 4z = p and 3x - 5y + 4z + 10 =0 . If the plane is perpendicular to the plane 3x - y - 2z - 4 = 0 , then the value of p is equal to