A lamina is made by removing a small disc of diameter 2R from a bigger disc of uniform mass density and radius 2R, as shown in the figure. The moment of inertia of this lamina about axes passing though O and P is `I_O and I_P` respectively. Both these axes are perpendiucalr to the plane of the lamina. The ratio `I_P/I_O` ot the nearest integer is

A lamina is made by removing a small disc of diameter 2R from a bigger disc of uniform mass density and radius 2R, as shown in the figure. The moment of inertia of this lamina about axes passing though O and P is I_O and I_P respectively. Both these axes are perpendicular to the plane of the lamina. The ratio I_P/I_O is

A disc has mass 9 m. A hole of radius R/3 is cut from it as shown in the figure. The moment of inertia of remaining part about an axis passing through the centre 'O' of the disc and perpendicular to the plane of the disc is :

A disc has mass 9 m. A hole of radius R/3 is cut from it as shown in the figure. The moment of inertia of remaining part about an axis passing through the centre 'O' of the disc and perpendicular to the plane of the disc is :

A square lamina is as shown in figure. The moment of inertia of the frame about the three axes as shown in figure I_(1),I_(2) and I_(3) respectively. Select the correct alternative.

A square lamina is as shown in figure. The moment of inertia of the frame about the three axes as shown in figure I_(1),I_(2) and I_(3) respectively. Select the correct alternative.

A lamina is made by removing a small disc of diameter 2 R from a bigger disc of uniform mass density and radius 2R, as shown in figure. A second similar disc is made but instead of hole a disc of triple the density as of first it filled in the hole. Centre of mass is calculated in both the cases and was found at a distance r_(1) & r_(2) from centre O respectively find the ratio |(2r_(2))/(r_(1))|

A lamina is made by removing a small disc of diameter 2 R from a bigger disc of uniform mass density and radius 2R, as shown in figure. A second similar disc is made but instead of hole a disc of triple the density as of first it filled in the hole. Centre of mass is calculated in both the cases and was found at a distance r_(1) & r_(2) from centre O respectively find the ratio |(2r_(2))/(r_(1))|

A thin disc of mass 9M and radius R from which a disc of radius R/3 is cut shown in figure. Then moment of inertia of the remaining disc about O, perpendicular to the plane of disc is -

A system of uniform rod of mass m and length 2R and a uniform disc of m and radius R are as shown in the figure. The moment of inertia of the system about the axis OO^' (perpendicular to plane of disc) will be