If `f(x)=|x+1|{|x|+|x-1|}` then number of points of in `[-2,2]` where `f(x)` is differentiable is

If f(x)=||x|-1| ,then the number of points where f(x) is not differentiable is

Let f(x)=|x|-1 ,then the number of points where f(x) is not differentiable is

Consider the function f(x)=min{|x^(2)-9|,|x^(2)-1|} , then the number of points where f(x) is non - differentiable is/are

Consider the function f(x)=min{|x^(2)-4|,|x^(2)-1|} , then the number of points where f(x) is non - differentiable is/are

Consider the function f(x)=min{|x^(2)-9|,|x^(2)-1|} , then the number of points where f(x) is non - differentiable is/are

Consider the function f(x)=min{|x^(2)-4|,|x^(2)-1|} , then the number of points where f(x) is non - differentiable is/are

The number of points in (1,3), where f(x)=a(([x^(2)]),a>1 is not differential is

The number of points in (1,3) , where f(x) = a(([x^2]),a>1 is not differential is

If f(x)=|x^(2)-3x+2|+|sinx| then number of points where f(x) is not differentiable in [-pi,pi] is