`(sqrt(sqrt(5)+2)+sqrt(sqrt(5)-2))/(sqrt(sqrt(5)+1))-sqrt(3-2sqrt(2))`

(sqrt(5)-2)(sqrt(3)-sqrt(5))

N=(sqrt(sqrt(5)+2)+sqrt(sqrt(5)-2))/(sqrt(5)+2)-sqrt(3-2sqrt(2)) then the value of N

N=(sqrt(sqrt(5)+2)+sqrt(sqrt(5)-2))/(sqrt(5)+2)-sqrt(3-2sqrt(2)) then the value of N

(sqrt(6+2sqrt(5)))(sqrt(6-2sqrt(5)))

(sqrt(3)-sqrt(5))(sqrt(3)+sqrt(5))/(sqrt(7)-2sqrt(5))

4 sin 27^(0)= 1) sqrt(5+sqrt(5))+sqrt(3-sqrt(5)) 2) sqrt(5-sqrt(5))+sqrt(3+sqrt(5) 3) sqrt(5+sqrt(5))-sqrt(3-sqrt(5)) 4) sqrt(5+sqrt(5))+sqrt(3+sqrt(5)

Simplify the following expressions: (4+sqrt(7))(3+sqrt(2))( ii) (3+sqrt(3))(5-sqrt(2))(sqrt(5)-2)(sqrt(3)-sqrt(5))(sqrt(5)+sqrt(2))(sqrt(3)+sqrt(2))

Find the value of (sqrt(sqrt(5)+sqrt(2))+sqrt(sqrt(5)-sqrt(2)))/(sqrt(sqrt(5)+sqrt(3)))

(2sqrt3+sqrt5)(2sqrt3+sqrt5)

((sqrt(3)+i sqrt(5))(sqrt(3)-i sqrt(5)))/((sqrt(3)+sqrt(2)i)-(sqrt(3)-i sqrt(2))