A particle moves in space such that its position vector varies as `vec(r)=2thati+3t^(2)hatj`. If mass of particle is 2 kg then angular momentum of particle about origin at `t=2` sec is

A particle moves on the xy-pane such that its position vector is given by vec(r)=3t^(2) hati-t^(3) hatj . The equation of trajectory of the particle is given by

A particle move in x-y plane such that its position vector varies with time as vec r=(2 sin 3t)hat j+2 (1-cos 3 t) hat j . Find the equation of the trajectory of the particle.

A particle move in x-y plane such that its position vector varies with time as vec r=(2 sin 3t)hat j+2 (1-cos 3 t) hat j . Find the equation of the trajectory of the particle.

A particle of mass 2 kg is moving such that at time t, its position, in meter, is given by vecr(t)=5hati-2t^(2)hatj . The angular momentum of the particle at t = 2s about the origin in kg m^(-2)s^(-1) is :

A particle of mass 2kg is moving such that at time t its position in meter is given by barr(t)=5hati-2t^(2)hatj . The angular momentum of the particle at t=2s about the origin in kgm^(-2)s^(-1) is

A particle moves in xy plane with its position vector changing with time (t) as vec(r) = (sin t) hati + (cos t) hatj ( in meter) Find the tangential acceleration of the particle as a function of time. Describe the path of the particle.

If postion vector of a particle is given by vec(r) = 10 alpha t^2 hati +[5 beta t- 5]hatj . Find time when its angular momentum about origin is O.

The position vector of a particle is given vecr= 2thati+3t^(2)hatj-5hatk calculate the velocity and speed of the particle at any instant 't'.