125^(2)=(25)/(5)" Sind "x

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If 125^(x)=(25)/(5^(x)), find x

125^(^^)x=25/(5^(^^)x)

If 25 ^(x+1) = (125)/( 5^(x)) , find the value of x.

Given log_(x)25 - log_(x) 5 = 2 - "log"_(x) (1)/(125) , find x.

The solution of (25)^(x -2) = (125)^(2x - 4) :

The value of x which satisfies 0.125xx4^(2x-8)=((0.25)/(sqrt(2)))^(-x)

If (5^2)^7=125^x , find x.