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A circular are of radius 1 subtends an a...

A circular are of radius `1` subtends an angle of `x` radians `0 < x < pi/2` as shown in the figure . the point `r` is the intersection of the two tangent line at `P` and `Q`. let `T(x)` be the area of triangle `PQR` and `S(x)` be the area of the shaded region then find `T(x) & S(x) & lim_(x->0)(T(x))/(S(x))`

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