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" (iii) "7^(2n+1)-:49=7^(3)...

" (iii) "7^(2n+1)-:49=7^(3)

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Find the value of n in each of the following: (i) 8xx2^(n+2)=32 (ii) 7^(2n+1)-:49=7^3

Find the value of n in each of the following: 8xx2^n^(+2)=32 (ii) 7^(2n)^(+1)-:49=7^3

49^(x)=7^(3)

Find the value of 'n' in each of the following : 7^(2n+1)div49=7^3

Simplify: (i) 4/9-:2/3 (ii) 3 3/7-:8/(21) (iii) 15 3/7-:1(23)/(49)

If A is square matrix of order 3 and |A| = 7 then the value of |adj A| is a) 47 b) 7 c) 49 d) 7^(3)

(49)^(2)xx (7)^(8)div (343)^(3)=(7)^(?)

If 7^(2)=49 nad 0.7^(2)=0.49 then 0.07^(2) =_________

Simplify: 4/9-:2/3 (ii) 3 3/7-:8/(21) 15 3/7-:1(23)/(49)

Find the sum to infinity of the series . (i) 1+ (2)/(11) + (3)/(121) + (4)/(1331) + … + n((1)/(11))^(n-1) + … (ii) 1 + (4)/(7) + (9)/(49) + (16) / (343) +…+ n^(2) ((1)/(7))^(n-1) +…