" 5,"x=sqrt(sin2 theta),y=sqrt(cos2 theta)

x=sqrt(sin2 theta),y=sqrt(cos2 theta) then find (dy)/(dx)

Find (dy)/(dx) , when x=sqrt(sin 2theta), y=sqrt(cos 2theta)

If x=sqrt(tan theta)-1 and y=sqrt((cos theta-sin theta)/(sin theta+cos theta)+2 then the value of )(2+2x+x^(2))(5-4y+y^(2)) is

int _(0)^(pi//2) (2sqrt(cos theta))/(3(sqrt(sin theta )+ sqrt(cos theta ))) d theta is equal to

If beta is one of the angles between the normals to the ellipse, x^2+3y^2=9 at the points (3 cos theta, sqrt(3) sin theta)" and "(-3 sin theta, sqrt(3) cos theta), theta in (0,(pi)/(2)) , then (2 cos beta)/(sin 2 theta) is equal to:

If y= sqrt(cos theta+sqrt(cos theta +sqrt(cos theta+......infty))), show that (dy)/(d theta) = (sin theta)/(1-2y)

If tan theta=(sin alpha- cos alpha)/(sin alpha+cos alpha) , then sin alpha+cos alpha =.................... A) sqrt2 cos, theta sqrt2 sintheta B) -sqrt2 sin theta, -sqrt2 cos theta C) sqrt2 sin theta , sqrt2 sin theta D) sqrt2 cos theta , - sqrt2 cos theta

" The value of the integral "int_(0)^( pi/2)(12sqrt(cos theta))/((sqrt(cos theta)+sqrt(sin theta))^(5))d theta" equals "...

If sin theta =sqrt 3/2,then cos theta=?