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[" Hor extd adt "],[(125)(3)/(2)]...

[" Hor extd adt "],[(125)(3)/(2)]

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125a^3+(1)/(8)

Find 125^((1)/(3))

Value of (125/343)^(2/3)=

sin [ 3 sin ^(-1) ((1)/(5)) ] is equal to : a) ( 71)/(125) b) (74)/(125) c) (3)/(5) d) (1)/(2)

root3(0.125)+3=

Find : 125^(-1/3) .

Simplify: (125)^((2)/(3))