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[" 44gam sample of a natural cas,consist...

[" 44gam sample of a natural cas,consisting of methane [CH,Jand clhylene [C,H "d" ] was bumed in excess "],[" of oxyyen yielding "132" gm "CO," and "som cH,O" as products.What is the mole "%" of ethylene in the "],[" semple? "]

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A 5.00 gm sample of a natural gas, consisting of methane CH_(4) , and ethylene, C_(2)H_(4) was burnt in excess oxygen , yeilding 44/3 gm of CO_(2) and H_(2)O as products . What mole percent of the sample was ethylene ?

A 5.0g sample of a natural gas consisting of CH_(4),C_(2)H_(4) was burnt in excess of oxygen yielding 14.5g CO_(2) and some H_(2)O as product. What is weight percentage of CH_(4) and C_(2)H_(4) in mixture?

A 10 gram sample of natural gas containing CH_(4) and C_(2)H_(4) was burnt in excess of oxygen to give 29.0 "grams" of CO_(2) and some water. How many games of water are formed :

A 10 gram sample of natural gas containing CH_(4) and C_(2)H_(4) was burnt in excess of oxygen to give 29.0 "grams" of CO_(2) and some water. How many games of water are formed :

A 10 gram sample of natural gas containing CH_(4) and C_(2)H_(4) was burnt in excess of oxygen to give 29.0 "grams" of CO_(2) and some water. How many grams of water are formed :

When 100 c.c. of a mixture of methane (CH_(4)) and ethylene (C_(2)H_(4)) was exploded with an excess of oxygen , the volume of carbon dioxide produced ( measured at the same temperature and pressure ) was 160 c.c. Calculate the heat evolved when 22.4 litre of the mixture of methane and ethylene ( measured at N.T.P. ) is completely oxidised to carbon dioxide and water at constant volume. CH_(4)+2O_(2)=CO_(2)+2H_(2)O+212000cal, C_(2)H_(4)+3O_(2)=2CO_(2)+2H_(2)O+333000 cal.