Q. if `(x-1)(x-2)(x+5)<0` then

Find the roots of the equations. Q. (2x)/(x-4)+(2x-5)/(x-3)=8(1)/(2) .

A : If (5x+1)/((x+2)(x-1))=A/(X+2)+B/(x-1) " then "A=3, B=2 . R : (px+q)/((x-a)(x-b))=(pa+q)/((x-a)(a-b))+(pb+q)/((b-a)(x-b)) .

A : If (5x+1)/((x+2)(x-1))=A/(X+2)+B/(x-1) " then "A=3, B=2 . R : (px+q)/((x-a)(x-b))=(pa+q)/((x-a)(a-b))+(pb+q)/((b-a)(x-b)) .

Number of integral solution of ((2x-3)^(2))/(16)<=1 is p and for -4<(x^(2))/(x)<=5 is q then find p and q

The HCF and LCM of the polynomials P(x) and Q(x) are (2x+3) and (2x+3)(x+5)(x-4)(x-2)(x+1) If P(x)=(2x+3)(x^(2)+x-20), then Q(x)=

(d)/(dx) [(x +1)(x^2+1)(x ^(4) + 1) (x ^(8) +1)]=(15 x ^(p) -16x^q+1) (x-1) ^(-2) implies (p,q)=

If P= (x^4-8x)/(x^3-x^2-2x), Q= (x^2+2x+1)/(x^2-4x-5) and R=(2x^2+4x+8)/(x-5) , then (PxxQ) div R is equal to: यदि P= (x^4-8x)/(x^3-x^2-2x), Q= (x^2+2x+1)/(x^2-4x-5) तथा R=(2x^2+4x+8)/(x-5) है, तो (PxxQ) div R का मान किसके बराबर है ?

(i) If p(x)=3x^(2)-5x+6 , find p(2) . (ii) If q(x)=x^(2)-2sqrt(2)x+1 , find q(2sqrt(2)) . (iii) If r(x)=5x-4x^(2)+3 find r(-1) .