Home
Class 11
PHYSICS
A planet whose size is the same and mass...

A planet whose size is the same and mass `4` times as that of Earth, find the amount of energy needed to lift a `2 kg` mass vertically upwards through `2m` distance on the planet. The value of `g` on the surface of Earth is `10 ms^(-2)`.

Promotional Banner

Similar Questions

Explore conceptually related problems

On a planet whose size is the same and mass 4 times as that of the Earth, find the amount of energy needed to lift a 2 kg mass vertically upwards through a distance 3 m of the planet. (value of g on the surface of th Earth is 10m//sec^(2) ).

On a planet whose size is the same and mass four times as that of our earth, find the amount of work done to lift 3 kg mass vertically upwards through 3 m distance on the planet. The value of g on the surface of earth is 10 ms^(-2)

On a planet whose size is the same and mass four times as that of our earth, find the amount of work done to lift 3 kg mass vertically upwards through 3 m distance on the planet. The value of g on the surface of earth is 10 ms^(-2)

On a planet (whose size is the same as that of earth and mass 4 times that of the earth ) the energy needed to lift a 2 kg mass vertically upwards through 2 m distance on the planet is (g = 10m// sec^(2) on surface of earth )

On a planet whose size is the same and mass is 3 times as that of the earth, calculate the energy required to raise a 5kg mass vertically upwars through a distance of 5m. Take g on earth = 10 m//s^(2)

A planet has the same size as that of the earth but its mass is 4 times the mass of the earth. What is the energy required to lift a stone of mass 5 kg vertically upwards through 3 m, on the planet ? [g on the surface of the earth = 10 m//s^(2) ]

The mass of a sphereical planet is 5 times the mass of the earth, but its diameter is the same as that of the earth. How much work is done in lifting a stone of mass 3 kg through a distance of 1 m on the planet ? [g on the surface the earth = 10 m//s^(2) ]

The mass of a planet and its diameter are three times those of earth's. Then the acceleration due to gravity on the surface of the planet is : (g =9.8 ms^(-2))