[" A potentiometer wire has length 'L'.For given cell of e.m.f.'E',the balancing length "],[" is "L/3" 'from the positive end of the wire.If the length of potentiometer wire is "],[" increased by "50%" then for the same cell,the balance point is obtained at length "]

The length of a potentiometer wire is l . A cell of emf E is balanced at a length l/3 from the positive end of the wire. If the length of the wire is increased by l/2. At what distance will the same cell give a balance point.

The length of a potentiometer wire is l . A cell of emf E is balanced at a length l/3 from the positive end of the wire. If the length of the wire is increased by l/2. At what distance will the same cell give a balance point.

The length of a potentiometer wires is l.A cell of emf E is balanced at a length ((l)/(3)) from positive end of the wire . If the length of the wire is increased by ((l)/(2)) the distance at which the same cell gives the balancing point is ( Cell in the primary is ideal and no series resistance is present in the primary circuit . )

The length of a potentiometer wire is 10 cm. A cell of emf E is balanced at a length 10/3 cm from the positive end of the wire. If the length of the wire is increased by 5 cm, at what distance (in cm) from positive end will the same cell give a balance point?

The length of a potentimeter wire is 10cm . A cell of emf E is balanced at a lenth (10)/(3) cm from the positive end of the wire .If the length of the wire is increased by 5 cm , at what distance (in cm ) from positive end will the same cell give a balance point ?

A potentiometer wire has resistance of per unit length of 0.1Omega//m . A cell of e.m.f. 1.5V balances against 300cm length of the wire. Find the current in the potentiometer wire.

A potentiometer wire has a resistance per unit length of 0.1 Omega//m . A cell of emf 1.5V balance against 300 cm length of the wire. Find the current through potentiometer wire.