[qquad g(x)=f(tan x)+f(cot x)AA x in((pi)/(2),pi)],[f''(x)<0AA x in((pi)/(2),pi)_(" then ")]

f(x)=Minimum{tan x,cot x}AA x in(0,(pi)/(2)) Then int_(0)^((pi)/(3))f(x)dx is equal to

The minimum value of the function f(x)=2tan x+3cot x where x in(0 ,(pi)/(2)) is

The minimum value of the function f(x)=2tan x+3cot x where x in(0, (pi)/(2)) is

The minimum value of the function f(x)=2tan x+3cot x where x in(0 (pi)/(2)) is

If f''(x) gt 0 AA x in R, f'(4) = 0 and g(x) = f ( cot^2 x - 2 cot x + 5) , 0 lt x lt (pi)/(2) , then

Let f(x)=(1-tan x)/(4x-pi),x!=(pi)/(4),x in[0,(pi)/(2)], If f(x) is continuous in [0,(pi)/(4)], then find the value of f((pi)/(4))

If f(x)=(sin x)/(x)AA x in(0,pi], prove that (pi)/(2)int_(0)^((pi)/(2))f(x)f((pi)/(2)-x)dx=int_(0)^( pi)f(x)dx

Let f'(sin x) 0AA x in(0,(pi)/(2)) and g(x)=f(sin x)+f(cos x), then