The equation of the circle which passes through the origin, center lies on the line x+y = 4 and cuts the circle `x^2 + y^2 - 4x + 2y +4 = 0` orthogonally :

The circle, which passes through the origin and whose centre lies on the line y = x and cutting the circle x^2+y^2-4x-6y+10 = 0 orthogonally is :

The equation of the circle which passes through the origin has its centre on the line x+y=4 and cuts orthogonally the circle x^2+y^2-4x+2y+4=0

Find the equation of the circle passing through the origin, having its centre on the line x + y = 4 and intersecting the circle x^2 + y^2 - 4x + 2y + 4 = 0 orthogonlly.

Find the equation of the circle passing through the origin, having its centre on the line x+y=4 and intersecting the circle x^2+y^2-4x+2y+4=0 orthogonally.

Find the equation of the circle passing through the origin, having its centre on the line x+y=4 and intersecting the circle x^2+y^2-4x+2y+4=0 orthogonally.

The equation of the circle which pass through the origin and cuts orthogonally each of the circles x^2+y^2-6x+8=0 and x^2+y^2-2x-2y=7 is