In fig. `/_B` of `/_\ABC` is an acute angle and `AD _|_ BC` ; prove that `AC^2 = AB^2 + BC^2 - 2 BC xx BD`

(Result on acute triangle) In Fig.4.184,/_B of ABC is an acute angle and AD perp BC, prove that AC^(2)=AB^(2)+BC^(2)-2BC xx BD

In a right-angled triangle,the square of hypotenuse is equal to the sum of the squares of the two sides.Given that /_B of /_ABC is an acute angle and AD perp BC .Prove that AC^(2)=AB^(2)+BC^(2)-2BC.BD

In a Delta ABC , angleB is an acute-angle and AD bot BC Prove that : (i) AC^(2) = AB^(2) + BC^(2) - 2 BC xx BD (ii) AB^(2) + CD^(2) = AC^(2) + BD^(2)

In triangleABC , angleB is an acute angle and AD botBC . Prove that AC^2= AB^2+BC^2-2BC.BD.

In a Delta ABC, /_ B is an acute-angle and AD bot BC . Prove that: AB^2 + CD^2 = AC^2 + BD^2

In Figure 2, AD _|_ BC . Prove that AB^2 + CD^2 = BD^2 + AC^2 .

In Fig if AD bot BC , prove that AB^2 + CD^2 = BD^2 + AC^2 .

In Fig.6.59, ABC is a triangle in which angleABC<90^@ and AD_|_BC .Prove that AC^2=AB^2+BC^2-2BC.BD .

In fig., ABC is triangle in which angleABC > 90@0 and AD bot BC produced, prove that AC^2 = AB^2 + BC^2 + 2BC.BD . .