`20 mL` of a weak monobasic acid `(HA)` requires `20 mL 0.2 M NaOH` for complete titration. If `pH` of solution upon addition of `10 mL` of this alkali to `25mL` of the above solution of `HA` is `5.8`. The `pK_(a)` of the weak acid is

50 ml of a weak acid , HA , required 30 ml 0.2 M NaOH for the end point . During titration , the pH of acid solution is found to be 5.8 upon addition of 20 ml of the above alkali . The pK_(a) of the weak acid is

50 ml of a weak acid , HA , required 30 ml 0.2 M NaOH for the end point . During titration , the pH of acid solution is found to be 5.8 upon addition of 20 ml of the above alkali . The pK_(a) of the weak acid is

A certain volume of a monobasic weak acid was titrated against 0.1 M NaOH solution . The end point reached upon addition of 30 ml of alkali . The pH of the solution upon the addition of 20 ml of alkali was 6.3 . Find K_(a) for the weak acid .

The equivalent point in a titration of 40.0mL of a sodium of a weak monoprotic acid occurs when 35.0mL of a 0.10M NaOH solutio has been added. The pH of the solution is 5.5 after the addition of 20.0mL of NaOH solution. What is the dissociation constant of the acid ?

The equivalent point in a titration of 40.0mL of a sodium of a weak monoprotic acid occurs when 35.0mL of a 0.10M NaOH solutio has been added. The pH of the solution is 5.5 after the addition of 20.0mL of NaOH solution. What is the dissociation constant of the acid ?

The equivalent point in titration of 40.0 ml of a solution of a weak monoprotic acid occurs when 35.0 of a 0.10 M NaOH solution has been added . The pH of the solution is 5.75 after the addition of 20.0 ml of NaOH solution . What is the dissociation constant of the acid ?

20 mol of M//10 CH_(3)COOH solution is titrated with M//10 NaOH solution. After addition of 16 mL solution of NaOH . What is the pH of the solution (pK_(a) = 4.74)

20 mol of M//10 CH_(3)COOH solution is titrated with M//10 NaOH solution. After addition of 16 mL solution of NaOH . What is the pH of the solution (pK_(a) = 4.74)