A S.H.M. is represented by `x= 5 sqrt2 (sin2pit+cos 2 pi t)` amplitude of the S.H. M is

A linear SHM is represented by x=5sqrt(2) ("sin" 2pi t+ "cos" 2pi t) cm. What is the amplitude of SHM ?

A simple harmonic motion is represented by F(t)=10sin(20t+0.5) . The amplitude of the S.H.M. is

The position of S.H.M. is given by x=2[√3sin πt +cos πt] . The amplitude of motion is [ x is in metre and symbols have the usual meaning]

The position of S.H.M. is given by x=2[√3sin πt +cos πt]. The amplitude of motion is [ x is in metre and symbols have the usual meaning]

The displacement of a particle executing a S.H.M. is given by x= A "sin" omega t +A "cos" omega t . What is the amplitude of motion ?

Equation of two S.H.M. x_(1)=5 sin (2pi t+pi//4),x_(2)=5sqrt(2)(sin 2pit+cos 2pit) ratio of amplitude & phase difference will be

The displacement of a particle in S.H.M. varies according to the relation x= 4 (cos pi t +sin pi t ) . The amplitude of the particle is

Equation of two S.H.M. x_(1)=5 sin (2pi t+pi//4),x_(2)=5sqrt(2)(sin 2pit+cos 2pit) ratio of amplitude & phase difference will be A. 2:1,0 B. 1:2,0 C. 1:2,pi//2 D. 2:1,pi//2

Two simple harmonic motions are represented by the equations x_1=5sin(2pit+pi/4) and x_2=5sqrt2(sin2pit+cos2pit) .The amplitude of second motion is ____ times the amplitude in first motion.