Evaluate `sum_(k=1)^(11)(2+3^k)`

Evaluate :sum_(k=1)^(10)(3+2^(k))

Evaluate sum_(k=0)^(5)k^(2)

"Evaluate "Sigma_(k=1)^(11) (2+3^(k))

"Evaluate "Sigma_(k=1)^(11) (2+3^(k))

Evaluate : sum_(k=1)^n (2^k+3^(k-1))

Evaluate : sum_(k=1)^n (2^k+3^(k-1))

Find the value off sum_(k=1)^10(2+3^k)

Find the value off sum_(k1)^10(2+3^k)

Evaluate : (i) sum_(n=1)^(10)(2+3^(n))" " (ii) sum_(k=1)^(n)[2^(k)+3^((k-1))]" " (iii) sum_(n=1)^(8) 5^(n)