`24x^2-41x+12`

Solve : 42x^2-41x-20 = 0 .

Using the first derivative , find the extreme of the following functions : f(x) =x^(4)-8x^(3)+22x^(2)-24x +12,

Factorise: 24x^2y+12x^2-12xy-6x

If the two roots of 9x^(3)+24x^(2)+13x+12x+2=0 are equal then the roots are

Divide 10x^(3) + 41x^(2) - 4x - 15 by 5x + 3 .

The polynomial function p is defined by p(x)=4x^(3)+bx^(2)+41x+12 , where b is a constant. When graphed on a standard coordinate plane, p intersects the x-axis at (-0.25, 0), (3, 0) and (k, 0) . What is the value of b?