If `theta` is the internal angle of `n` sided regular polygon, then `sintheta` is equal to:

What is sum of the interior angles of a regular polygon of n sides?

If phi is the exterior angle of a regular polygon of n sides and theta is any constant then prove that sin theta+sin(theta+phi)+sin(theta+2 phi)+... upto n terms =0

The limit of the interior angle of the regular polygon of n sides as nto oo is

The difference between the exterior angles of two regular polygons, having the sides equal to (n-1) and (n+1) is 9^@. Find the value of n.

If the sum of the roots of the equation sin^(2)theta=k,(0ltk lt 1) lying in [0,2pi] is equal to the angles of a n-sided regular polygon, then the value of n is

If the sum of the roots of the equation sin^(2)theta=k,(0ltk lt 1) lying in [0,2pi] is equal to the angles of a n-sided regular polygon, then the value of n is

The sum of the internal angles of a regular polygon is 1440^(@) . The number of sides is :

If the difference between an exterior angle of a regular polygon of 'n' sides and an exterior angle of another regular polygon of '(n+1)' sides is equal to 5^(@) , find the value of 'n'.