The rate constant for a forward reaction in a reversible reaction `(k_(eq)=10^(6))` is `10^(2)` the rate constant for its backward "

In a chemical equilibrium, the rate constant for the backward reaction is 7.5xx10^(-4) and the equilibrium constant is 1.5 the rate constant for the forward reaction is:

In a reaction A+BhArrC+D the rate constant of forward reaction & backward reaction is K_(1) and K_(12) then the equilibrium constant (K) for reaction is expressed as:

For a system in equilibrium, the rate constant for the forward reaction is represented by K_f and the rate constant for the reverse reaction is represented by K_r .Which equation represents the equilibrium constant for this reaction in the forward direction ?

For the reaction : A+2B ? AB_(2) , the rate of forward reaction is (dx)/(dt) =1xx10^(5) [A] [B]^(2)-1xx10^(4) [AB_(2)] . The rate constants for forward and backward reactions are :