\(CuSO_{4}\) Solution reacts with hypo (taken excess) and form a complex \(Na_{x}[Cu_{y}(S_{2}O_{3})_{z}\) .Value of x+y-z" is

CuSO_(4) solution reacts with excess of KCN solution to form:-

In iodometric estimation of Cu^(2+) ion, the following reaction took place 2Cu^(2+)+4ItoCu_(2)I_(2)+I_(2) I_(2)+2Na_(2)S_(2)O_(3)to2NaI+Na_(2)S_(4)O_(6) If 100mL OF CuSO_(4) solution added to excess KI requires 50mL of 0.2M Na,S_(2)O_(3) the molarity of CuSO_(4) solution is :

638.0 g of CuSO_(4) solution is titrated with excess of 0.2 M KI solution. The liberated I_(2) required 400 " mL of " 1.0 M Na_(2)S_(2)O_(3) for complete reaction. The percentage purity of CuSO_(4) in the sample is

AgCl dissolved in excess of NH_(3), KCN and Na_(2)S_(2)O_(3) solutions the complex produces ions

632 g of sodium thiosulphate (a_(2)S_(2)O_(3)) reacts with copper sulphate to form cuproc thiosulphate which is reduced by sodium thiosulphate to give cuprous compound which is dissolved in excess of sodium thiosulphate to form a complex compound sodium cuprothisosulphate (Na_(4)[Cu_(6)(S_(2)O_(3))_(5)]) , (MW=1033) CuSO_(4) + Na_(2)S_(2)O_(3) rarr CuS_(2)O_(3) + Na_(2)SO_(4)" " [very fast] 2CuSO_(4)+Na_(2)S_(2)O_(3)+Na_(2)S_(2)O_(3) rarr Cu_(2)S_(2)O_(3) + Na_(2)S_(4)O_(6) 3Cu_(2)S_(2)O_(3) + 2Na_(2)S_(2)O_(3) rarr Na_(4)[Cu_(6)(S_(2)O_(3))_(5)] " " (Sodium cuprothisoulphate ) In this process , 0.2 mole of sodium cuprothiosulphate is formed .(O=16 , Na=23 , S=32) It instead of given amount of sodium thiosulphate, 2 moles of sodium thiosulphate along with 3 moles of CuSO_(4) were taken initially . Then, moles of sodiu cuprothiosulphate formed is: