A body is projected obliquely from the ground with a speed 'u' and at an angle "'theta with the horizontal.It's velocity at the maximum height is (A) zero (B) u sin theta,(C) u cos theta (D) u

A particle is fired from a point on the ground with speed u making an angle theta with the horizontal.Then

For a projectile first with velocity u at an angle theta with the horizontal.

A body is projected from the ground with a initial velocity vecu an angle theta with the horizontal. Speed with which it strikes the ground (A) u costheta (B) u sintheta (C) u (D) none

A body is projected with speed u at an angle theta to the horizontal to have maximum range. Its velocity at the highest point will be ___.

STATEMENT-1: A body is projected from the ground with a velocity v at an angle with the horizontal direction, it reaches a maximum height (H) and reaches the ground after a time T = 2u sin theta//g because STATEMENT-2: The vertical and horizontal motions can be treated independently

A body of mass m is projected with intial speed u at an angle theta with the horizontal. The change in momentum of body after time t is :-

If a projectile is fired at an angle theta with the vertical with velocity u, then maximum height attained is given by:-

A particle is thrown with speed u at an angle theta with horizontal. Find the average velocity of particle: (a) O to C (b) A to B ( c) O to H

A projectile is fired at an angle theta with the horizontal with velocity u. Deduce the expression for the maximum height reached by it.