A body is projected from the ground with a initial velocity `vecu` an angle `theta` with the horizontal. Speed with which it strikes the ground
(A) `u``costheta` (B) `u``sintheta` (C) `u` (D) none

For a projectile first with velocity u at an angle theta with the horizontal.

A ball is projected from the ground with velocity u such that its range is maximum Then

A particle is projected form ground with velocity u ar angle theta from horizontal. Match the following two columns.

A particle is fired from a point on the ground with speed u making an angle theta with the horizontal.Then

A body is projected obliquely from the ground with a speed 'u' and at an angle "'theta with the horizontal.It's velocity at the maximum height is (A) zero (B) u sin theta,(C) u cos theta (D) u

STATEMENT-1: A body is projected from the ground with a velocity v at an angle with the horizontal direction, it reaches a maximum height (H) and reaches the ground after a time T = 2u sin theta//g because STATEMENT-2: The vertical and horizontal motions can be treated independently

A body of mass m is projected with intial speed u at an angle theta with the horizontal. The change in momentum of body after time t is :-

A ball of mass m is projected from the ground with an initial velocity u making an angle of theta with the vertical. What is the change in velocity between the point of projection and the highest point ?

A projectile is projected with velocity u making angle theta with horizontal direction, find : horizontal range.