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K(2)Cr(2)O(7) in alkaline medium with "3...

`K_(2)Cr_(2)O_(7)` in alkaline medium with "30%`H_(2)O_(2)` forms red- brown compound "(X)" . Oxidation state of Cromium "X" , is +a and number of peroxy oxygens in "X'" is "b'" . Value of "(b-a)" is

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\(K_{2}Cr_{2}O_{7}\) in alkaline medium with \(30\%\) \(H_{2}O_{2}\) forms red-brown compound (X). Oxidation state of Cr in 'X' is '+a' and number of peroxy oxygens in 'X' is 'b' .Value of (b-a) is

Oxidation state of oxygen in H_(2)O_(2) is

The oxidation state of Cr in K _ 2 Cr _ 2 O _ 7 is

The oxidation state of Cr in Cr_(2)O_(7)^(2-) is

When mixture of NaCl and K_(2)Cr_(2)O_(7) is gently warmed with conc. H_(2)SO_(4) then compound X is formed. What is the oxidation state of central atom of X?

The oxidation state of Cr in K_(2)Cr_(2)O_(7) is:

When K_(2)Cr_(2)O_(7) is treated with H_(2)O_(2) in acidic medium, in presence and in absence of org. solvent. The oxidation state of chromium finally:

K_(2)Cr_(2)O_(7)+SO_(2) overset(H+)to products the oxidation state of chromium changes from