A body projected with a velocity `u` at an angle `alpha` with the vertical. Its time of ascent is
(A) `u``sin alpha``//``g`
(B) `u``cosalpha``//``g`
(C) `2u``sinalpha``//``g`
(D) `2u``cosalpha``//``g`

A body is projected from the ground with a initial velocity vecu an angle theta with the horizontal. Speed with which it strikes the ground (A) u costheta (B) u sintheta (C) u (D) none

" A body is projected with velocity u making an angle 30^(0) with the horizontal.Its velocity when it is perpendicular to the initial velocity vector is "

A body is projected obliquely from the ground with a speed 'u' and at an angle "'theta with the horizontal.It's velocity at the maximum height is (A) zero (B) u sin theta,(C) u cos theta (D) u

A body projected vertically upwards with a velocity u returns to the starting point in 4 seconds. If g = 10m//sec , the value of u is

A body is projected vertically upwards with some velocity u . It at the same point at t = 6 s as was at t = 4 s . Find the value of u .

A particle is projected with a velocity u making an angle theta with the horizontal. At any instant its velocity becomes v which is perpendicular to the initial velocity u. Then v is

An particle is projected with velocity u on an inclined plane at an angle theta with the plane. If the particle lands on the plane at right its time of flight is (u cosec theta)/(2 g) . Find the angle of inclination of the plane with horizontal.

If intsinx/(sin(x-alpha))dx=Ax+Blogsin(x-alpha)+C , then value of (A,B) is (A) (-sinalpha,cosalpha) (B) (-cosalpha,sinalpha) (C) (sinalpha,cosalpha) (D) (cosalpha,sinalpha)