A gaseous mixture of three gases A, B and C has a pressure of 10 atm. The total number of moles of all the gases is 10. If the partial pressure of A and B are 3.0 and 1.0 atm respectively and if C has a mol/wt. of 2.0. what is the weight of C in g present in the mixture ?

A gaseous mixture contains three gaseous A,B and C with a total number of moles of 10 and total pressure of 10 atm . The partial pressure of A and B are 3 atm and 1 atm respectively and if C has molecular weight of 2 g //mol . Then, the weight of C present in the mixture will be :

In a mixture of equal weights of H_(2) and He gases at pressure of "6" atm the partial pressure of helium is "

Partial pressure of CH_(4) gas in the mixture of CH_(4) & He gases in a flask is 0.5 atm. If that mixture is at STP, the weight of helium gas in the mixture is

A gaseous mixture of 2 moles of A, 3 moles of B, 5 moles of C and 10 moles of D is contained in a vessel. Assuming that gases are ideal and the partial pressure of C is 1.5 atm, total pressure is

The pressure of a mixture of equal weight of two gases of mol wt. 4 and 40, is 1.1 atm. The partial pressure of the lighter gas in this mixture is

A methane +H_(2) mixture contains 10g methane and 5g Hydrogen. If the pressure of the mixture is 30 atm. What is the partial pressure of H_(2) in moxture :-