Heat released is called Lattice enthalpy in the case of
(А) \(Na(s)+\frac{1}{2}Cl_{2}(g)\rightarrow NaCl(s)\)
(В) \(Na^{+}(g)+Cl^{-}(g)\rightarrow NaCl(s)\)
(C) \(Na^{+}(g)+Cl{-}(g)\rightarrow NaCl(g)\)
(D) all of these

Consider the following changes: \(M(s)\rightarrow M(g)\) \(M(s)\rightarrow M^{2+}(g)+2e^{-}\) ,\(M(g)\rightarrow M^{+}(g)+e^{-}\) \(M^{+}(g)\rightarrow M^{2+}(g)+e^{-}\) \(M(g)\rightarrow M^{2+}(g)+2e^{-}\). The second ionization energy of M could be calculated form the energy values associated with

For the reaction aA(s) + bB(g) rightarrow dD(s) + cC(g) . Then

DeltaG^(@) of the cell reaction AgCl(s) + 1/2H_(2) rightarrow Ag(s) + H^(+) + Cl^(-) is -21.52kJ . DeltaG^(@) of 2AgCl(s) + H_(2)(g) rightarrow + 2H^(+) + 2Cl^(-) is

DeltaG^(@) of the cell reaction AgCl(s) + 1/2H_(2) rightarrow Ag(s) + H^(+) + Cl^(-) is -21.52kJ . DeltaG^(@) of 2AgCl(s) + H_(2)(g) rightarrow + 2H^(+) + 2Cl^(-) is

Which terms are exothermic for the formation of NaF(s) ? (P) Na(g) rarr Na^(+) (g)+e^(-) (Q) F(g)+e^(-) rarr F^(-)(g) (R) Na^(+)(g)+F^(-)(g) rarr NaF(s)

For the reaction PCI_(5)(g) rightarrow PCI_(3)(g) + CI_(2)(g)

For which one of the following reaction,the graph of Delta G against T is almost horizontal to temperature axis (А) C_((s)) + O_(2(g)) rarr CO_(2(g)) (В) 2C_((s)) + O_(2(g)) rarr 2CO_((g)) (с) 2CO_((s)) + O_(2(g)) rarr 2 CO_(2(g)) (D) 2Mg_((s)) + O_(2(g)) rarr 2 MgO_((s))

If, H_(2)(g)+Cl_(2)(g)rarr 2HCl(g) , Delta H^(@)=-44 Kcal 2Na(s)+2HCl(g)rarr 2NaCl(s)+H_(2)(g), Delta H=-152 Kcal Then, Na(s)+0.5Cl_(2)(g)rarr NaCl(s) , Delta H^(@) = ?

H_(2)(g) + Cl_(2) rarr 2HCl (g), Delta H = -44K.cals 2 Na(s)+2HCl (g)rarr 2NaCl(s)+H_(2)(g), Delta H = -152K.cal Na(s)+(1)/(2)Cl_(2)(g) rarr NaCl(s), Delta H = ?