The intensity of gravitational field at the centre of a ring of mass m and radius R is (A) Zero (B)(Gm)/(2r^(2) (C) "(Gm)/(r^(2) (D) (2Gm)/(r^(2)

Calculate gravitational field intensity at a distance x on the axis from centre of a uniform disc of mass M and radius R .

Calculate the gravitational field intensity at the centre of the base of a hollow hemisphere of mass M and radius R . (Assume the base of hemisphere to be open)

If mass of earth is M ,radius is R and gravitational constant is G,then work done to take 1kg mass from earth surface to infinity will be (A) sqrt((GM)/(2R)) (B) (GM)/(R)] (C) sqrt((2GM)/(R))]

The magnitude of the gravitational field at distance r_(1) and r_(2) from the centre of a uniform sphere of radius R and mass M are F_(1) and F_(2) respectively. Then:

The magnitudes of the gravitational field at distance r_(1) and r_(2) from the centre of a uniform sphere of radius R and mass M are E_(1) and E_(2) respectively. Then:

Find the centre of mass of a uniform semicircular ring of radius R and mass M .

Assertion : The centres of two cubes of masses m_(1) and m_(2) are separated by a distance r. The gravitational force between these two cubes will be (Gm_(1)m_(2))/(r^(2)) Reason : According to Newton's law of gravitation, gravitational force between two point masses m_(1) and m_(2) separated by a distance r is (Gm_(1)m_(2))/(r^(2)) .