A body of mass m is projected from ground with speed u at an angle `theta` with horizontal. The power delivered by gravity to it at half of maximum height from ground is

A body of mass m is projected with intial speed u at an angle theta with the horizontal. The change in momentum of body after time t is :-

A bomb of mass m is projected from the ground with speed v at angle theta with the horizontal. At the maximum height from the ground it explodes into two fragments of equal mass. If one fragment comes to rest immediately after explosion, then the horizontal range of centre of mass is

A particle is projected with a speed v at an angle theta with the horizontal. Find the mean power delivered by gravity during the ascent of the particle.

A particle of mass m is thrown with speed u at an angle of projection theta with horizontal. The average power imparted by the gravitational force until it strikes the ground is

A particle is fired from a point on the ground with speed u making an angle theta with the horizontal.Then

A body is projected from ground with velocity u making an angle theta with horizontal. Horizontal range of body is four time to maximum height attained by body. Find out (i) angle of projection (ii) Range and maximum height in terms of u (iii) ratio of kinetic energy to potential energy of body at maximum height

A body is projected obliquely from the ground with a speed 'u' and at an angle "'theta with the horizontal.It's velocity at the maximum height is (A) zero (B) u sin theta,(C) u cos theta (D) u

A particle of mass m is projected with an initial velocity U at an angle theta to the horizontal. The torque of gravity on projectile at maximum height about the point of projection is

A particle is projected from ground with speed u and at an angle theta with horizontal. If at maximum height from ground, the speed of particle is 1//2 times of its initial velocity of projection, then find its maximum height attained.