In `DeltaABC` with usual notation,`(c-b cos A)/(a)` is equal to

In Delta ABC with usual notation, (c-b cos A)/(a) is equal to

The any DeltaABC under usual notation ,a(bcos C-c cosB) is equal to

Given (b+c)/(11)=(c+a)/(12)=(a+b)/(13) for a DeltaABC with usual notation. If (cos A)/(alpha)=(cos B)/(beta)=(cos C)/(gamma) then the ordered traiad, (alpha,beta,gamma) has a vlaue

In DeltaABC , with usual notations, if cosA=(sinB)/(sinC) , then the triangle is

Given (b+c)/(11) = (c+a)/(12) = (a+b)/(13) for a Delta ABC with usual notation. If (cos A)/(alpha) = (cos B)/(beta) = (cos C)/(gamma) , then the ordered triad (alpha, beta, gamma) has a value:

In any DeltaABC under usual notation, a(bcosC-c cosB) =

In a Delta ABC with usual notations, if (a)/(cos A)=(b)/(cos B)=(c )/(cos C) , then the triangle is :

In DeltaABC , with usual notations, (bsinB-c sin C)/(sin(B-C))= . . . .

In DeltaABC , with usual notations, if a,b,c are in AP then acos^(2)((C)/(2))+cos^(2)((A)/(2))=