A running man has half the KE that a body of half his mass has. The man speeds up by `1.0ms^(-1)` and then has the same energy as the boy. What were the original speeds of the man and the boy?

A man who is running has half the kinetic energy of a boy of half his mass. The man speeds up by 1 ms^(-1) and then has the same kinetic energy as the boy. The original speed of the boy was:

A running man has the same kinetic energy as that of a boy of half his mass. The man speed up by 2 ms^(-1) and the body changes his speed by x ms^(-1) so that the kinetic energies of the boy and the man are again equal. Then x in ms^(-1) is

A man has twice the mass of a boy and has half the kinetic energy of the boy. The ratio of the speeds of the man and the boy must be

A lady running on the road has kinetic energy that is half of that of girl . The girl's mass is half of the lady's mass. The lady increases her speed y m/s and then has the same energy as of girl . Calculate the original speeds of the lady and the girl .