The total length of a sonometer wire fixed between two bridges is 110 cm. Now, two more bridges are placed to divide the length of the wire in the ratio `6:3:2`. If the tension in the wire is 400 N and the mass per unit length of the wire is `"0.01 kg m"^(-1)`, then the minimum common frequency with which all the three parts can vibrate, is

The length of a sonometer wire between two fixed ends is 110cm. Where should the two bridges the placed so as to divide the wire into three segments, whose fundamental frequencies are in the ration 1:2:3?

The total length of a sonometer wire between fixed ends is 110 cm. To bridges are placed to divide the length of the wire in ratio 6 : 3 : 2. What is the minimum common frequency with which three parts can vibrate? Also calculate the ratio of number of loops formed in three parts. The tension in the wire is 400 N and the mass per unit length is 0.01 kg//m .

The length of a sonometer wire is 1m. Where should be the bridge placed to divide the wire into 2 segments, whose fundamental frequencies are in the ratio 1: 2 ?

The tension produced in a sonometer wire is 60 N and the length between two bridges is 40 cm. The length of wire is 1 m and the mass of the wire is 2g. The speed of transverse waves produced in the wire is

A wire connected in the left gap of a meter bridge balance a 10Omega resistance in the right gap to a point, which divides the bridge wire in the ratio 3:2. If the length of the wire is 1m. The length of one ohm wire is

Two steel wires of equal volume are stretched with the same tension. If the lengths of the wires are in the ratio 1:2 the ratio of their extensions will be

The length of a wire between the two ends of a sonometer is 105 cm. Where should the two bridges be placed so that the fundamental frequencies of the three segments are in the ratio of 1:3:15?

The length of the stretched sonometer wire is 1m, if the fundamental frequency are in the ratio 1:2 . Where should be the bridge be placed to divide the wire two segments ?