A charge `Q` is divided into two parts `q_(1)` and `q_(2)` such that they experience maximum force of repulsion when separated by certain distance. The ratio of `Q,q_(1)` and `q_(2)` is

A charge fo magnitude Q is divided into two parts q and (Q - q) such that the two parts exert maximum force on each other. Calculate the ratio Q//q .

A charge is divided into two charges q and (Q-q) .The value of q so that force between them is maximum is equal to

A charge Q is divided into two parts of q and Q -q . If the coulomb repulsion between them when they are separated is to be maximum, the ratio of Q/q should be

A charge Q is divided into q and Q - q. If Q/q = x , such that repulsion between them is maximum, find x.

A total charge Q is broken in two parts Q_(1) and Q_(2) and they are placed at a distance R from each other. The maximum force of repulsion between them will occur, when

Two point charges Q and - Q //4 are separated by a distance X . Then .

A certain charge Q is divided into two parts q and Q-q , wheich are then separated by a cetain distance. What must q be in terms of Q to maximum the electrostatic repulsion between the two charges?

A charge Q is divided into two parts. Charge on each part is q. Also, Q//q=2 . What is the Columbic force between two charges q and q when both parts are placed certain distance apart?