If the earth were to suddenly contract to `1//n^(th)` of its present radius without any change in its mass, the duration of the new day will be nearly

If the earth suddenly contracts to one third of its present size without any change in its mass, the ratio of the kinetic energies of the earth after and before contraction will be

If the earth were to suddenly contract to half of its present radius (without any external torque on it), by what duration would the day be decreased ? Assume earth to be perfect solid sphere of radius (2)/(5)MR^(2) .

If the radius of the earth contracts to half of its present value without change in its mass, what will be the new duration of the day?

If radius of the earth contracts to half of its present value without change in its mass, what will be the new duration of the day?

Imagine that the earth suddenly contracts to one-third of its present radius, without any external torque on it. By what duration the day on the earth will decrease considering the earth to be a perfect solid sphere.

If the radius of the earth shrinks by "25%" without change in its mass,the time duration of one day will be "

If the earth suddenly contracted to half of its present radius without losing any mass, how many hours would there be in a day? (hint: Apply the principle of conservation of angular momentum).

the escape velocity on a planet is v. if the radius of the planet contracts to 1/4 of the present value without any change in its mass, the escape velocity will be

If radius of earth becomes n times its present value, without change in mass, then duration of day becomes