Find the modulus of average acceleration (in m/s2) of the block from time t = 2 sec to t = 4 sec.

A particle is moving along straight line whose position x at time t is described by x = t^(3) - t^(2) where x is in meters and t is in seconds . Then the average acceleration from t = 2 sec. to t = 4 sec, is :

The velocity time graph of a body moving in a straight line is shown. Find its (a) instantaneous velocity at t = 1.5 sec (b) average acceleration from t = 1.5 sec. to t = 2.5 sec (c) draw its acceleration time graph from t = 0 to t = 2.5 sec

Velocity vector of a particle is given as vecv=4thati+3hatj At t=0 position of the particle is given as vecr_(0)=2hatj Find the position vector of the particle at t=2 sec and te average acceleration of the particle for t=0 to t=2sec.

A particle starts from rest and moves with an acceleration of a={2+|t-2|}m//s^(2) The velocity of the particle at t=4 sec is

Acceleration of a particle is given by a= 3t^(2)+2t +1 Where t is time . Find (i) its velocity at time t assuming velocity to be 10 m/s at t = 0. (ii) its position at time t assuming that the particle is at origin at t = 0. (iii) What is the average speed of the particle in the duration t = 0 to t = 1s? (iv) What is the average acceleration of the particle in the duration t = 0 to t = 1s?

A particle is moving in a circle of radius 4 cm with constant speed of 1 cm//s. Find (a) time period of the particle. (b) average speed, average velocity and average acceleration in a time interval from t=0 to t = T/4. Here, T is the time period of the particle. Give only their magnitudes.

Position of a particle at any instant is given by x = 3t^(2)+1 , where x is in m and t in sec. Its average velocity in the time interval t = 2 sec to t = 3 sec will be :

During one dimensional motion on x-axis Velocity time graph for particle is given. Average acceleration between (t = 0 sec) to (t = 6 sec)

The time period of an oscillator is 8 sec. the phase difference from t = 2 sec to l = 4 sec will be :-