From a circle of radius a, an isosceles right angles triangle with the hypotenuse as the diameter of the circle is removed. The distance of the centre of mass of the remaining portion from the centre of the circle is

A square hole is punched out of a circular lamina, the diagonal of the square being the radius of the circle. If 'a' be the diameter of the sircle, find the distance of centre of mass of the remainder from the centre of the circle.

A uniform sphere has radius R . A sphere of diameter R is cut from its edge as shown. Then the distance of centre of mass of remaining portion from the centre of mass of the original sphere is

From a uniform circular dis of radius R , a circular dis of radius R//6 and having centre at a distance R//2 from the centre of the disc is removed. Determine the centre of mass of remaining portion of the disc.

If a circle is inscribed in right angled triangle ABC with right angle at B, show that the diameter of the circle is equal to AB+BC-AC.

A diameter of a circle is a chord that………the centre.

AD is the diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, the distance of AB from the centre of the circle is