The moment of inertia of a uniform rod about a perpendicular axis passing through one end is `I_(1)`. The same rod is bent into a ring and its moment of inertia about a diameter is `I_(2)`. Then `I_(1)//I_(2)` is

The M.I. of a uniform rod about a perpendicular axis passing through one of its ends is I_(1) . The same rod is bent into a ring and its moment of inertia about a diameter is I_(2) . Then (I_(1))/(I_(2)) is

The moment of inertia of a uniform ring about an axis passing through its centre and perpendicular to its plane is 100kgm^(2) . What is the moment of inertia of the ring about its diameter ?

Moment of inertia of a ring of mass M and radius R about an axis passing through the centre and perpendicular to the plane is I. What is the moment of inertia about its diameter ?

Derive an expression for the moment of inertia of thin uniform rod about an axis passing through its one end. Also find the radius of gyration.

Moment of inertia of a thin uniform rod about an axis passing through one end perpendicular to its length is I . Then moment of inertia the same rod about the central axis perpendicular to its plane is

Calculate the moment of inertia of a rod of mass M, and length l about an axis perpendicular to it passing through one of its ends.

Moment of inertia of a straight wire about an axis perpendicular to the wire passing through one of its end is I. This wire is now framed into a circle (a ring) of single turn. The moment of inertia of this ring about an axis passing through centre and perpendicular to its plane would be