Area bounded by `y=tan x, y=tan^2x` in between `x in (-pi/3,pi/3)` is equal to `(pi/4+lnsqrt(2)-1)`

Area bounded by y=tan x,y=tan^(2)x in between x in(-(pi)/(3),(pi)/(3)) is equal to ((pi)/(4)+ln sqrt(2)-1)

The area bounded by y=tan x,y=cot x,x axis in 0<=x<=(pi)/(2) is

The area bounded by curves y = tan x, x-axis and x= pi/3 is-

The area bounded by the curve y=cosx and y=sin 2x, AA x in [(pi)/(6), (pi)/(2)] is equal to

What is the area bounded by y = tan x, y = 0 and x =pi/4 ?

The area bounded by the curve y=sin x between x=(pi)/(2) and x=(3 pi)/(2)

Area bounded by y=[tan x] with (pi)/(12) (ii) (pi)/(6) (iii) between x=0 and x=(pi)/(3) is (i) (pi)/(12) (ii) (pi)/(6) (iii) (2 pi)/(3) (iv) none of these

Area bounded by the curve y=max{sin x, cos x} and x -axis, between the lines x=(pi)/(4) and x=2 pi is equal to

Area bounded by y=|x-(pi)/(2)| and x=0,x=pi equals

Find the area bounded by y= sec^(2) x , x = pi/6, x = pi/ 3 & x-axis