The foci of the hyperbola `(x+1)^2/64-(y-2)^2/36=1` are

The foci of the hyperbola 3(y-1)^2-4(x-2)^2=12 are (0,sqrt(7)) b. (-2,1-sqrt(7)) c. 2,1-sqrt(7) d. (0)-sqrt(7)

The foci of the hyperbola (x^(2))/(16) -(y^(2))/(9) = 1 is :

The foci of the hyperbola 4x^(2)-9y^(2)-1=0 are

The foci of the hyperbola 4x^(2)-9y^(2)-1=0 are