AB is the chord on the parabola `y^2=4ax` with its vertex at A. BC is drawn perpendicular to AB meeitng the axis at C. The projection of BC on the axis of the parabola is :

AB is a chord of the parabola y^(2)=4ax with its vertex at A.BC is drawn perpendicular to AB meeting the axis at C.The projecton of BC on the axis of the parabola is

OA is the chord of the parabola y^(2)=4x and perpendicular to OA which cuts the axis of the parabola at C. If the foot of A on the axis of the parabola is D, then the length CD is equal to

AB is a focal chord of the parabola y^(2)=4ax If A=(4a,4a) then B=

The vertex A of the parabola y^(2)=4ax is joined to any point P on it and PQ is drawn at right angles to AP to meet the axis in Q. Projection of PQ on the axis is equal to

If AB is a focal chord of the parabola y^(2)=4ax whose vertex is 0, then(slope of OA ) x (slope of OB)-

Write the length of het chord of the parabola y^(2)=4ax which passes through the vertex and in inclined to the axis at (pi)/(4)

Length of the chord of the parabola y^(2)=4ax passing through the vertex and making an angle theta (0< theta < pi ) with the axis of the parabola

Through the vertex of the parabola y^(2)=4ax , chords OA and OB are drawn at right angles to each other . For all positions of the point A, the chord AB meets the axis of the parabola at a fixed point . Coordinates of the fixed point are :