Product of perpendiculars drawn from the foci upon any tangent to the ellipse `3x^(2)+4y^(2)=12` is

Prove that the product of the perpendiculars from the foci upon any tangent to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is b^(2)

The product of perpendiculars from the focii upon any tangent of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is b^(2)

Locus of foot of perpendicular drawn from the centre (0,0) to any tangent on the ellipse kx^(2)+3y^(2)=2 is 3kx^(2)+4y^(2)-6(x^(2)+y^(2))^(2)=0 then the value of (1)/(e^(2)) ( where e is eccentricity of the ellipse) is ......

The locus of the foot of the perpendicular drawn from the centre on any tangent to the ellipse x^2/25+y^2/16=1 is:

Find the locus of the foot of the perpendicular drawn from the center upon any tangent to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1

If the locus of the foot of the perpendicular drawn from centre upon any tangent to the ellipse (x^(2))/(40)+(y^(2))/(10)=1 is (x^(2)+y^(2))^(2)=ax^(2)+by^(2) , then (a-b) is equal to

The locus of the foot of the perpendicular from the foci an any tangent to the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 , is